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After applying exponentially, or even polynomially many random local gates to a fixed input state, the resulting distribution of the output state $\lvert\psi_{out}\rangle$ will (be very close) to Haar random. This gives a procedural way of generating Haar-random states, given the ability to apply gates from a fixed gate set: generate some random circuit and take the output.

My question: is there a similar procedure for generating a (close to) Haar-random state conditioned on the state having low entanglement entropy (say constant)?

One attempt to generate low-entanglement states could be to apply a random-constant depth circuit instead of, say, a polynomial depth circuit, but this would not suffice for Haar-randomness. I have seen the concept of a random matrix product state here, but don't have the background to determine to what extent this setup coincides with the Haar-random definition above.

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    $\begingroup$ Regarding "After applying exponentially, or even polynomially many random local gates to a fixed input state, the resulting distribution of the output state $|\psi\rangle$ will (be very close) to Haar random - is this correct? Wouldn't we need a doubly-exponential number of such gates? See, e.g., here. $\endgroup$ Commented Jul 1 at 16:40
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    $\begingroup$ @MarkSpinelli Yeah, I didn't really specify what I meant by very close to random, I was thinking close enough for an application which relies on a distribution which shares similar properties to the Haar-random distribution (such as random circuit sampling, pseudorandom states, etc). Thanks for the link! $\endgroup$
    – Ben Foxman
    Commented Jul 1 at 18:07
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    $\begingroup$ I think that works - random circuits of polynomial size share some properties with the Haar-random distribution, related to "approximate t-designs" (whatever those are). $\endgroup$ Commented Jul 1 at 19:22

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It is important to be precise what you mean by Haar-random here. Consider a Hilbert space $\mathcal{H}$ of dimension $d$. If you want to integrate over the Haar measure on $U(d)$, then the average entanglement entropy will not be constant in $d$.

If you are interested in a random matrix ensemble with bounded entanglement entropy, a matrix product state (MPS) ansatz as in your reference is a reasonable choice. If you fix the bond dimension $\chi$ you have a constant entanglement entropy by construction. Drawing $n$ Haar-random unitaries for the MPS, however, refers to the Haar measure on $U(\chi)^{\otimes n}$, which is a smaller space, in general.

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    $\begingroup$ Thanks, my question is a bit imprecise as stated. I'll edit the question to clarify. $\endgroup$
    – Ben Foxman
    Commented Jul 1 at 18:12

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