Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
DO NOT use this tag. Use more specific tags such as [linear-algebra] instead.
3
votes
Can I find the states of individual qubits in a quantum register using only linear algebra?
Here's a simple method that will work on any state that is not entangled with other qubits. It's also pretty efficient; it's the method used by the amplitude displays in Quirk.
Find the index $k$ of …
1
vote
Accepted
Why do we search for square roots of 1 in Shor's algorithm unlike the quadratic sieve?
The two problems are equivalent.
If you give me a pair $a, b$ such that $a^2 = b^2$ with $a \neq \pm b$ then $c = a b^{-1}$ satisfies $c \neq \pm 1$ and $c^2 = 1$.
If you give me a $c$ such that $c^ …
3
votes
In Shor's factorization algorithm for $N$, why can we always find $n$ such that $N^2\le 2^n\...
If $2^k$ is less than $x$, you can increase $k$ by 1 without exceeding $2x$. Because if $2^k < x$ then $2 \cdot 2^k < 2 \cdot x$ and so $2^{k+1} < 2x$. If you start at $k=0$ and keep incrementing, $2^ …
6
votes
Accepted
What is the HOG test and how would it help proving quantum supremacy?
There are a couple variants of the HOG test.
"Old HOG" computed the proportion of unique samples whose probability is larger than the median probability of the distribution. It then compares that pro …