# What does "an $n$-qubit array can represent $2^n$ possible array elements" mean?

I read "...an $$n$$ qubit array can represent $$2^n$$ possible array elements.." on this post. A classical $$n$$-bit array can represent $$2^n$$ possible array elements as well, so I'm confused about the difference. Does it mean that the $$2^n$$ possibilities represented by the $$n$$-qubit array are represented at the same time?

Now here is where it gets deep an 𝑛 Qubit Array can represent $$2^𝑛$$ possible array elements (consult anywhere online for an explanation of that or drop a comment).
And similarly an 𝑛 Qubit quantum operator can act on that entire $$2^𝑛$$ quantum space, and produce an answer that we can interpret.
It's probably not too clear here, but I think the OP meant, an $$n$$ qubit array can represent any state that is a linear combination of $$2^n$$ basis states.
So, a classical array of 1 bit could represent any state 0 or 1 ($$2^1$$ possibilities), but a single qubit could be in any state $$\alpha |0\rangle + \beta |1\rangle$$ where $$|\alpha|^2 + |\beta|^2 = 1$$, so an infinite number of possibilities made from a basis of $$2^n$$ states.