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The X gate in the $|+\rangle$, $|-\rangle$ basis becomes the Z gate and vice versa.

What is the Pauli Y gate as a matrix transformation in the $|+\rangle$, $|-\rangle$ basis?

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  • $\begingroup$ What do you mean by X gate become Z gate? Does it mean that Z in Hadamard basis transform basis states between each other as X gate in computational basis? If so, please note that Y works similarly in circular basis. $\endgroup$ Commented May 15, 2022 at 7:18

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We have,

$Y=i|+\rangle\langle -| -i|-\rangle\langle +|$

You can calculate it easily using the fact that,

$|0\rangle = \frac{1}{\sqrt 2}(|+\rangle + |-\rangle)$,

$|1\rangle = \frac{1}{\sqrt 2}(|+\rangle - |-\rangle)$, and

$Y = i|1\rangle\langle 0| -i|0\rangle\langle 1|$

So, it has the same matrix up to a sign change.


Alternative solution is to use what you already mentioned in your question:

The X gate in the $|+\rangle$, $|-\rangle$ basis becomes the Z gate and vice versa

with the fact, $Y=iXZ$, and $XZ = -ZX$.

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