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Nov 6, 2023 at 18:02 history edited glS CC BY-SA 4.0
edited title
Nov 6, 2023 at 18:01 comment added glS generally speaking, a map of the form $\Phi(X)=UXU^\dagger$ has Choi $\sum_{ij} \Phi(E_{ij})\otimes E_{ij}$ equal to $\operatorname{vec}(U)\operatorname{vec}(U)^\dagger$ (that is, $uu^\dagger$ with $u$ the vectorization of $U$)
Nov 4, 2023 at 3:18 vote accept karry
Nov 3, 2023 at 13:49 review Suggested edits
Nov 4, 2023 at 1:41
S Nov 3, 2023 at 7:42 history suggested FDGod
added relevant tag
Nov 3, 2023 at 7:42 review Suggested edits
S Nov 3, 2023 at 7:42
Nov 3, 2023 at 7:30 answer added FDGod timeline score: 3
Nov 3, 2023 at 6:43 history asked karry CC BY-SA 4.0