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Any $2\times2$ matrix can be expressed as the sum and product of the identity, Pauli $X$ and Pauli $Z$ matrices. This is often used to express a singe-qubit state using just Pauli matrices. One can then use tensor products of single-qubit states and take linear combinations to build $n$-qubit states.

If I use the Heisenberg picture and I am interested in an arbitrary single-qubit observable, I can always write it as a sum and product of Pauli $X$ and $Z$ observables because it is just a $2\times2$ matrix.

But can I then write an $n$-qubit observable in terms of these single-qubit observables always by taking tensor products and linear combinations?

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    $\begingroup$ Yes. It just might require exponentially many of them. $\endgroup$
    – DaftWullie
    Commented Jul 18 at 13:27
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    $\begingroup$ Does this or this answer your question? $\endgroup$
    – Tristan Nemoz
    Commented Jul 18 at 15:36
  • $\begingroup$ Yes, my question is a duplicate. Thank you $\endgroup$ Commented Jul 19 at 6:15

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