Timeline for Non-entangled two qubit system get information about the individual particle states after CNOT
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 7, 2019 at 6:33 | vote | accept | Bob Person | ||
| Dec 7, 2019 at 4:33 | comment | added | ss09 | That's great! We're all learning. Happy to help. | |
| Dec 7, 2019 at 4:30 | comment | added | Bob Person | Oh right, it's just algebra. For some reason I got tangled up in the QM notation and expected there to be some magical matrix or vector manipulation I could do. Thanks, this solved my problem :) | |
| Dec 7, 2019 at 4:28 | comment | added | ss09 | Apologies, I'm working on my formatting skills in order to better present my answer. But I'll try my best here. It's just like doing FOIL with the expression (ax+by)(cx+dy). Imagine x and y are your |0> and |1> states. So, we'll be left with coefficients ac, ad, bc and bd for the different terms in expanded expression. You could do the same in reverse. Another way to think about it is factoring out common coefficients from the expression. Did it help? If not, I'll try to come up with a better way to present this. | |
| Dec 7, 2019 at 4:20 | comment | added | Bob Person | So to find alpha and beta I would need to do an inverse tensor product. Could you explain how you would do that please, if you can. | |
| Dec 7, 2019 at 4:17 | history | answered | ss09 | CC BY-SA 4.0 |