Timeline for Why is the quantum Fisher information for pure states $F_Q[\rho,A]=4(\Delta A)^2$?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 18, 2020 at 18:03 | comment | added | John Doe | Yes that's correct, I overlooked that we are interested only in $|0\rangle$ since it is a pure state. | |
| Jan 18, 2020 at 17:52 | comment | added | AHusain | Write the two terms. One is an expectation value of A^2 while the other is expectation value of A squared. | |
| Jan 18, 2020 at 12:02 | comment | added | John Doe | How do you know that $$ \langle 0 |A \bigg( \mathbb{I} - |0\rangle\langle 0| \bigg) A| 0 \rangle = (\Delta A)^2? $$ | |
| Oct 17, 2019 at 9:16 | vote | accept | John Doe | ||
| Oct 16, 2019 at 23:19 | history | answered | AHusain | CC BY-SA 4.0 |