Timeline for How to factor the output of a CNOT acting on the input $|-,+\rangle$
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 2, 2019 at 9:42 | answer | added | peawormsworth | timeline score: 1 | |
| Sep 10, 2019 at 5:24 | vote | accept | leloctai | ||
| Sep 9, 2019 at 15:54 | answer | added | glS♦ | timeline score: 2 | |
| Sep 9, 2019 at 15:06 | comment | added | leloctai | @glS I'm looking for a generic way to factor the result, so that I can implement it using classical code. I'm thinking there are too possible way, one is to detect which qbit is changed, and handle each case. That would require knowing why the CNOT act the way it does. However, if there is a generic way to factor the vector without knowing one of the input, then that would be what I'm most interested in | |
| Sep 9, 2019 at 13:39 | comment | added | glS♦ | is the question about how to realise that that particular length-four vector can be written as tensor product of two length-2 vectors, or about why the CNOT seems to change the control qubit in this case? | |
| Sep 9, 2019 at 13:36 | history | edited | glS♦ | CC BY-SA 4.0 |
edited title
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| Sep 9, 2019 at 6:57 | answer | added | DaftWullie | timeline score: 2 | |
| Sep 9, 2019 at 5:10 | review | First posts | |||
| Sep 9, 2019 at 8:00 | |||||
| Sep 9, 2019 at 5:08 | history | asked | leloctai | CC BY-SA 4.0 |