Timeline for How to find an equivalent circuit without ancilla qubits?
Current License: CC BY-SA 4.0
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| Mar 15 at 11:27 | comment | added | upe | I made an edit to my question in the hope to clarify it. I assume the 2 ancilla qubits have the initial state $|i\rangle = (|0\rangle + i|1\rangle ) / \sqrt{2}$ and $U$ is an arbitrary quantum gate, so not necessarily self-inverse. But, if I can eliminate the ancilla qubits for a self-inverse $U$ gate that would already help me. | |
| Mar 10 at 19:37 | history | edited | Craig Gidney | CC BY-SA 4.0 |
added 2 characters in body
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| Mar 10 at 19:24 | history | answered | Craig Gidney | CC BY-SA 4.0 |