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Mar 31, 2023 at 15:26 vote accept Loic Stoic
Mar 31, 2023 at 7:00 comment added Michele Amoretti In that case you get $|\psi'\rangle = \frac{1}{\sqrt{3}}(|10\rangle + |11\rangle + |01\rangle)$. It is linear algebra, so you just apply the gate to each of the superposed elements of your state.
Mar 31, 2023 at 6:16 comment added Andrew Baker What if $| \psi \rangle = \frac{1}{\sqrt{3}}( | 00 \rangle + | 01 \rangle + | 11 \rangle )$ being applied in a CNOT? In this case, there are two kets that have a “0” qubit in them.
Mar 31, 2023 at 6:01 history answered Michele Amoretti CC BY-SA 4.0