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Jun 1, 2022 at 1:37 comment added Evangeline A. K. McDowell @NorbertSchuch Actually something that always bugs me is whether this theorem implies 2-positivity is enough to prove CP, since your proof essentially says that if it's 2-positive then it's true for $k > 2$. I have never seen this connection stated clearly.
May 10, 2022 at 9:02 vote accept glS
May 10, 2022 at 7:17 comment added Norbert Schuch @gls ... or my 4 using the SVD of M :) In fact, this is one of the advanced questions I like asking in oral exams, if everything goes smoothly ;) (Will have to remember to delete this comment! :-o)
May 10, 2022 at 7:07 comment added glS sure. I just like this equation because it gives a direct explicit relation answering the question: "how does the action of $\Phi\otimes\operatorname{Id}_k$ on a generic state $|\chi\rangle$ relate to the action on maximally entangled states?". It's essentially your point 4, yes, observing that the matrix $D$ is just the diagonal matrix whose elements are the Schmidt coefficients
May 9, 2022 at 22:54 comment added Norbert Schuch If D is singular this is a one-way relation. But isn't this precisely my point 4?
May 9, 2022 at 21:47 comment added glS ah, nice, this is the kind of thing I was hoping for. One could also make a trivial modification to the argument to make it "positive" I think: $$(\Phi\otimes\operatorname{Id}_k)(|\chi\rangle\!\langle\chi|)=(I\otimes D)[(\Phi\otimes\operatorname{Id}_n)(|\Omega\rangle\!\langle\Omega|)](I\otimes D)$$ with $D$ diagonal matrix with the Schmidt coefficients of $\chi$, so that we get a direct relation between positivity on $|\Omega\rangle$ and positivity on arbitrary (pure) states
May 8, 2022 at 23:53 history edited Norbert Schuch CC BY-SA 4.0
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May 8, 2022 at 23:38 history edited Norbert Schuch CC BY-SA 4.0
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May 8, 2022 at 23:33 history answered Norbert Schuch CC BY-SA 4.0