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Nov 22 at 14:05 answer added Mark Spinelli timeline score: 0
Nov 23, 2021 at 7:01 history edited glS CC BY-SA 4.0
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Nov 19, 2021 at 20:31 comment added Mark Spinelli The beginning of page 2 of the paper provides the answer. "Clearly, to read out all the components of $\vec x$ would require one to perform the procedure at least $N$ times. However, often one is interested not in $\vec x$ itself, but in some expectation calue $\vec x^T M\vec x$, where $M$ is some linear operator (our procedure also accommodates nonlinear operators as described below)."
Nov 19, 2021 at 20:27 history edited Mark Spinelli CC BY-SA 4.0
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Nov 19, 2021 at 20:18 history asked Mark234 CC BY-SA 4.0