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Jan 14, 2020 at 17:23 comment added Kelthar Is decomposition also intractable for unitaries that are composed solely by the multiplication of clifford gates? I'm looking to build a random circuit generator, and I'd like to insert an inversion layer after the random gates, in order to end up with a deterministic (in this case, equal to the initial) state. However, instead of just mirroring the circuit, I was wondering it is possible to efficiently compute an inversion layer if the input circuit is solely made up of Cliffords?
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May 13, 2018 at 18:51 vote accept user120404
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May 13, 2018 at 15:12 history answered rrtucci CC BY-SA 4.0