Timeline for Why attenuator and not filters for QC driving line
Current License: CC BY-SA 4.0
9 events
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Mar 7, 2021 at 19:18 | vote | accept | Marco Fellous-Asiani | ||
Mar 7, 2021 at 19:18 | history | bounty ended | Marco Fellous-Asiani | ||
Mar 4, 2021 at 19:51 | comment | added | user1271772 No more free time | You're very welcome! About point (4), it's not just that "dissipation is not always bad I guess", it's that dissipation is required for some types of quantum transport, and a bit of it is good for quantum annealing, but I agree that it is "almost always an enemy" for circuit-based quantum computing (keep in mind that an adiabatic quantum computer is also a "quantum computer"). I was just quoting what the paper said "dissipation is anyway desired in order to thermalize the incoming radiation fields". Point (2) is important: attenuators were better than non-attenuating filters. | |
Mar 4, 2021 at 19:46 | history | edited | user1271772 No more free time | CC BY-SA 4.0 |
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Mar 2, 2021 at 9:25 | comment | added | Marco Fellous-Asiani | In the very end: I guess the real answer is the point about performance that you described. Maybe it is just the best that we can do in practice to avoid blackbody radiation to enter to the qubits and this is just a "practical" issue that one day will probably be removed. | |
Mar 2, 2021 at 9:25 | comment | added | Marco Fellous-Asiani | About point (4). It is true for quantum simulation that dissipation is not always bad I guess. But for quantum computer the noise is almost always an ennemy. However I don't agree with your argument that says attenuation is desired. I think what they mean is that we need to avoid noise to enter the qubit. Attenuation is a solution. As we will typically attenuate the signals if the wire in themself are attenuating it is not a problem in the end | |
Mar 2, 2021 at 9:24 | comment | added | Marco Fellous-Asiani | Thank you for your very detailed answer. About point (3): what I have in mind is a filter that reflects all frequencies to mimic an attenuator. Instead of dissipating into heat the signal (and noise), it just reflects them. I guess a 3-port non dissipative device would do the job. | |
Mar 2, 2021 at 1:30 | history | edited | user1271772 No more free time | CC BY-SA 4.0 |
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Mar 2, 2021 at 1:17 | history | answered | user1271772 No more free time | CC BY-SA 4.0 |