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Sep 3, 2020 at 7:54 history edited JSdJ CC BY-SA 4.0
edited body
Sep 2, 2020 at 3:31 vote accept BlackHat18
Sep 1, 2020 at 16:12 comment added user1936752 Ah I see, thank you!
Sep 1, 2020 at 15:13 comment added JSdJ @user1936752 I've added some extra discussion; note that $|\rho - \sigma| = \sqrt{(\rho - \sigma)^{\dagger}(\rho - \sigma)}$, which is not a number.
Sep 1, 2020 at 15:11 history edited JSdJ CC BY-SA 4.0
added explanation
Sep 1, 2020 at 14:49 comment added user1936752 I don't understand the part where you say $|\rho - \sigma| = Q+S$. The left hand side is a number while the right hand side is an operator. I don't have a copy of the book but would you mind clarifying this bit so the answer is self-contained?
Sep 1, 2020 at 13:07 history answered JSdJ CC BY-SA 4.0