Timeline for How do I check if a gate represented by Unitary $U$ is a Clifford Gate?
Current License: CC BY-SA 4.0
7 events
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| May 17, 2022 at 12:55 | comment | added | Niel de Beaudrap | @quest: In some cases, a unitary operation may leave the states of some qubits apparently unchanged when they are in the standard basis (as with a controlled operator). More generally, it may map a standard basis state of some qubits, to a different standard basis state. The parameter $n-k$ is basically determined by how many qubits this is true for. I don't think that this parameter has a name, as such, or represents some quantity that people investigate much — hopefully someone will correct me if I'm wrong on this point — though it is likely to be important in general for circuit synthesis. | |
| May 17, 2022 at 2:03 | comment | added | quest | Thank you very much for this great answer and forgive my ignorance but what is the k here? It is the column itself or index of the column or index of the first non zero column or first column which has non zero entry? | |
| Aug 4, 2020 at 14:52 | history | edited | Niel de Beaudrap | CC BY-SA 4.0 |
Minor clarifications and revisions
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| Aug 4, 2020 at 14:40 | history | edited | Niel de Beaudrap | CC BY-SA 4.0 |
Corrected errors and added improved techniques
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| Aug 4, 2020 at 13:16 | history | edited | Niel de Beaudrap | CC BY-SA 4.0 |
Fixed typos
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| Aug 4, 2020 at 12:37 | vote | accept | vasjain | ||
| Aug 4, 2020 at 12:09 | history | answered | Niel de Beaudrap | CC BY-SA 4.0 |