Timeline for How to construct quantum circuit to count number of 0-qubits and 1-qubits
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 14, 2022 at 11:09 | comment | added | DaftWullie | @Alternative7 Yes, sorry. Can't edit comments... | |
| Jan 14, 2022 at 10:57 | comment | added | Alternative7 | Ah, now I got it. You mean IZI, not IZZ, for the middle term, right? | |
| Jan 14, 2022 at 9:56 | comment | added | DaftWullie | No, the summation is not their tensor product. $\sum_{j=1}^j$Z_j$ means $Z\otimes I\otimes I+I\otimes Z\otimes Z+I\otimes I\otimes Z$. | |
| Jan 14, 2022 at 9:19 | comment | added | Alternative7 | So the summation of the Pauli Z is their tensor product? I assume that H is a 8x8 matrix with 3 qubits, and since they're not under superposition the number of 1s is indicated by the location of single 1 among the elements in their state vector. (For ex, if the state vector is {10000000}^T, that means none of the qubits are in 1) Did I understand it right? | |
| Jan 14, 2022 at 8:08 | comment | added | DaftWullie | @Alternative7 Yes, $Z_j$ is the Pauli $Z$ matrix applied to qubit $j$ (tensored with identities on all other qubits) | |
| Jan 13, 2022 at 16:04 | comment | added | Alternative7 | Could you explain what the summation of Z_j represents? Is it a Pauli matrix? | |
| Jul 27, 2020 at 1:45 | vote | accept | Isomorphism | ||
| Jul 15, 2020 at 7:32 | history | answered | DaftWullie | CC BY-SA 4.0 |