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Ian Gershon Teixeira's user avatar
Ian Gershon Teixeira's user avatar
Ian Gershon Teixeira's user avatar
Ian Gershon Teixeira
  • Member for 2 years, 4 months
  • Last seen this week
6 votes
Accepted

Finite subgroup of $U(4)$ containing a non-Clifford gate and all local Cliffords

5 votes
Accepted

Building universal gate set for $SU(d^n)$ from universal gate set for $SU(d)$

5 votes
Accepted

Qutrit Steane Code

5 votes
Accepted

Which codes have transversal $T$ gate?

4 votes
Accepted

Why does fault-tolerant transversal phase gate $P$ only work with doubly-even codes?

4 votes
Accepted

Are all stabilizer codes real? Or example stabilizer codes with $\pm i$ coefficients

3 votes

Is the controlled-Hadamard gate in the Clifford group?

2 votes
Accepted

What is an example of a non-additive code that is not a CWS code?

2 votes

Example non-stabilizer code?

2 votes

Is there a "simple" way to tell if a stabilizer code is degenerate?

2 votes
Accepted

The Clifford hierarchy and $ e^{2 \pi i/2^k} $

2 votes

Is there a way to write a generic low dimensional Clifford matrix?

2 votes
Accepted

What are well-known orthogonal 2-designs, other than the real Clifford group?

2 votes

List of codes which can perform non-Clifford gates fault-tolerantly

2 votes

Does a quantum channel always preserve the identity matrix?

2 votes

Is the Eastin-Knill Theorem incorrect?

2 votes
Accepted

Weakly transversal gates for the $ [[15,1,3]] $ quantum Reed-Muller code

1 vote
Accepted

Example of code where codewords cannot be stabilizer states

1 vote

Weight enumerators for Hermitian operator

1 vote

Generators for single qudit Clifford, d=4

1 vote

Equivalent definition of distance for nondegenerate code

1 vote

What are the possible non-entangling two-qubit gates?

1 vote
Accepted

Is the Clifford group superperfect?

1 vote
Accepted

Which monomial matrices are in the Clifford hierarchy?

1 vote

Fault Tolerance of 2-transversal gates

1 vote
Accepted

Recognizing a CWS code in a specific case

1 vote

Magic state distillation: why is it harder to prepare the encoded $|A_{\pi/4}\rangle$ than $|0 \rangle$