New answers tagged


Short, sort-of right answer: you can't This is in essence due to the superconducting qubits that e.g. IBM use being, well, qubits, while continuous variable (CV) operations don't act on qubits. Well, sort of. These are two fundamentally different ways of going about making a quantum computer, so let's start from first principles: When you take a state $\...

Top 50 recent answers are included