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-1 votes
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How is Magic State Distillation (MSD) compatible with Stabiliser Measurement?

Question is solved! EDIT: Where I was wrong was thinking that somehow, because the T-gate cannot be transversally implemented, that this would disrupt stabiliser outcomes. They don't. Stabilisers can ...
JoJo P's user avatar
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5 votes
Accepted

How do magic states circumvent the Eastin-Knill theorem?

The important distinction here is not between Clifford and non-Clifford. It's between transversal and non-transversal. The Eastin-Knill theorem simply says that you cannot create a universal set of ...
DaftWullie's user avatar
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1 vote

Does the preparation of magic states need magic gates?

Yes, preparing a non-Clifford state (a "magic state") requires a non-Clifford gate (a "magic gate"). I've not heard the term "magic gate" before so it's possible that you ...
Craig Gidney's user avatar
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0 votes

Does the preparation of magic states need magic gates?

No. Using the encoding map is just a way to produce stable source of raw magic states. The fidelity of the raw state depends on the quality of your quantum hardware, which can actually be much higher ...
Yunzhe's user avatar
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3 votes
Accepted

Does the preparation of magic states need magic gates?

An example of universal quantum computation scheme using magic states can be found in this paper. What is shown there is that if you have access to several copies of noisy magic states, you can purify ...
AG47's user avatar
  • 476

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