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2 votes

Do we consider the entangled-based protocol E91 to be a device-independent protocol?

Ekert's original protocol was never specified in a device independent way but, as you suggest, it's very close by virtue of the reliance on Bell inequalities. (He has commented to me that, with ...
DaftWullie's user avatar
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1 vote

Do we consider the entangled-based protocol E91 to be a device-independent protocol?

I think you can safely say that E91 was the beginning of device-independent protocols. It has all the basic ideas in there and the intuition for why device-independent security holds is there too. ...
Rammus's user avatar
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0 votes
Accepted

In e91 protocol, if one of the bases combination was not chosen, what should be done to avoid division by zero?

The question boils down to how you should infer probabilities from relative frequencies, and that is a hotly disputed subject. Usually this is swept under the carpet by assuming that the number of ...
Mateus Araújo's user avatar
0 votes

In a QKD protocol such as BB84 how do Alice and Bob deal with lost or undetected photons?

To address this, the BB84 protocol involves several steps to maintain security and establish a shared key even when some photons are lost: Shared Basis Announcement: After sending the qubits, Bob ...
Shravan Patel's user avatar
2 votes

In a QKD protocol such as BB84 how do Alice and Bob deal with lost or undetected photons?

If the photons are sent sequentially, they can implement some synchronous control and detect the missed bits by timing. Also, they could implement additional control using public non-encrypted ...
dariox's user avatar
  • 121
2 votes

Benefits of using quantum encrypted keys

A classical asymetric cipher is based on computationaly hard problems (assumed to be as so far we have not found an efficient algorithm). This means that classical computer is believed to be incapable ...
Martin Vesely's user avatar
2 votes
Accepted

Entanglement-based attack on E91 protocol

It doesn't matter which maximally entangled two-qubit state Alice and Bob share. They're all the same up to the action of a unitary on one of the qubits, which is just the same as changing the ...
DaftWullie's user avatar
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