# Tag Info

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### Are GHZ states absolutely maximally entangled?

I think the issue here is the definition of Absolutely Maximally Entangled (AME) states on Wikipedia, which you are quoting. I had not heard of AME states before, but after coming across your question,...
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### GHZ Definition - Does it all have to be $|000\ldots\rangle$ or $|111\ldots\rangle$ or can it be $|010\ldots\rangle$ or $|101\ldots\rangle$

TL;DR: No, these are not GHZ states. They are cat states. GHZ state The GHZ state is defined as the state $$\frac{|000\rangle+|111\rangle}{\sqrt{2}}.\tag1$$ Generalized GHZ ...
• 24.2k
Accepted

### Output of my quantum circuit to create 3-qubit GHZ-like state does not make sense mathematically

As @Callum said, your ordering of qubit is wrong. Qiskit keeps the 0th qubit at the rightmost space in a ket representation or for measurement. If you have, say 3 qubits, qubit#1, qubit#2, qubit#3, in ...
• 2,418
Accepted

• 14k

### Why does measuring a GHZ state in the computational basis destroy the entanglement?

The two-qubit GHZ state (Bell state) case is special: any measurement in a basis $$\cos\theta X+\sin\theta Z$$ will return perfectly correlated results between the two parties. In the case of a ...
• 60.7k

### What is the general form for GHZ and W class states?

The GHZ form of the state follows from a bit of a manipulation after define what you mean by a GHZ state, remembering that all these parametrisations are "up to local unitaries". For me, the ...
• 60.7k
1 vote

• 121
1 vote

### Transferring GHZ state onto some qubits

About checking. I do not quite understand why you can't check how the GHZ-state was teleported in the most ordinary ways: in addition to measuring the state immediately after teleportation, as well as ...

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