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In the situation described in the book, Alice and Bob share the state $$|\psi\rangle = \frac{|00\rangle+|11\rangle}{\sqrt{2}}.$$ Using the definition $|\pm\rangle=(|0\rangle\pm|1\rangle)/\sqrt2$ and simple algebra we can see that $|\psi\rangle$ can also be written $$|\psi\rangle = \frac{|{++}\rangle+|{--}\rangle}{\sqrt{2}}.$$ Now, if Alice measures \$|\...