New answers tagged cirq
2
As Craig said, you applied b_big and a_big differently. The adjoint a_big is missing from your product. Try rotated_state = b_big @ a_big @ state @ a_big.conj().T @ b_big.conj().T. But Craig's right. Using Circuits would be much simpler:
import itertools
import random
import cirq
import numpy as np
def chsh_circuit(i, j, qs):
return cirq.Circuit(cirq.H(...
3
Assuming $x$ is $n$ bits, here's a simple procedure: take $n$ ancilla qubits, all prepared in $|0\rangle$. Do a transversal controlled-not (i.e. bit by bit controlled-not) from the register with $|x\rangle$ to the ancilla register. THis means that if you started wuth
$$
\sum_xa_x|x\rangle,
$$
you now have
$$
\sum_xa_x|x\rangle|x\rangle.
$$
Next, find a bit ...
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