New answers tagged bell-basis
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Measuring one qubit in an entangled pair in another basis?
Yes, and no!
If you have some basis change unitary $U$ for a single qubit, then the person holding the first qubit can perform that unitary on their qubit, using the mathematical description $U\otimes ...
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creating a generalised Bell state with gates
I think I nailed it.
The 4 Bell states are
$$\frac{1}{\sqrt{2}}\big
[|00\rangle + |11\rangle\big],\quad \frac{1}{\sqrt{2}}\big[|01\rangle + |10\rangle\big],\quad \frac{1}{\sqrt{2}}\big[|00\rangle - |...
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creating a generalised Bell state with gates
Starting from any of the four basis states, Hadamard + controlled-not will produce each of the four Bell states. So, expressed in terms of the gates you need, you just need to add $X$ to either qubit ...
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