Questions tagged [bell-basis]
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15
questions
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Creating Bell states (a question from tutorial)
I was going through a Quantum Computation lecture series on YouTube given by Umesh Vazirani. There in Lecture 6.3 he talks about creating a Bell state using a Hadamard and CNOT gate. He seems to be ...
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0answers
30 views
Constructing and Measuring in an Arbitrary 3-qubit basis
As part of a Quantum Theory project I have "constructed" an arbitrary 3-qubit basis:
$\left|B_0\right> =\left|000\right>$
$\left|B_1\right> = \frac{1}{\sqrt{2}}\cos(x)(\left|100\right> +...
1
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0answers
26 views
Bell states from EPR pair of two-level atoms [closed]
Considering a case in which we prepare an entangled EPR pair from two two-level atoms interacting with a cavity, one prepared in ground state and the other in excited state but moving in at a later ...
2
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2answers
63 views
How to measure in the bell basis?
The question is quite straightforward, I have some two qubit state and I want to measure it in the Bell basis. This question answers me partly, but I still have some doubts because, I thought that ...
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0answers
31 views
Do Bell state measurements satisfy the completeness condition from the no-signalling theorem?
Do Bell state measurements satisfy the completeness condition from the no-signalling theorem?
In a quantum experiment involving unitary evolution and projective measurements, do Bell state ...
2
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3answers
116 views
No Schmidt decomposition for tripartite states
Exercise 2.77 in Nielsen and Chuang asks to show by example that there exist tripartite states $| \psi \rangle_{ABC} $ which cannot be written as
$$| \psi \rangle = \sum_i \lambda_i | i_A \rangle | ...
1
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1answer
128 views
Is back in time (classical) information transfer possible (based on delayed choice entanglement swapping)?
Delayed choice entanglement swapping.
Two pairs of entangled photons are produced, and one photon from each pair is sent to a party called Victor. Of the two remaining photons, one photon is sent to ...
2
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2answers
112 views
What is the property of any entangled pair of qubits?
We know that any of the Bell states has the special property that the second qubit will be found in a state which is predictable based on measuring one of the qubits. But assuming any other pair of ...
3
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1answer
67 views
Problem with quantum tomography on two qubits
With reference to question on how to do quantum tomography on two qubits, I would like to ask you for help again. I tried to do the tomography on state
\begin{equation}\psi=\frac{1}{2}\begin{pmatrix}...
2
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1answer
178 views
Transforming the first Bell state into the other Bell states
As I understand it, you can transform the different Bell states into one another by applying various gates. Wikipedia has the Bell states written out as follows:
And says that you can generate bell ...
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1answer
46 views
Find the Bell States of A and B in the following scenario
Let A has quantum memories $M_1$ and $M_2$ and B has quantum memories $M_3$ and $M_4$ capable of holding one qubit.
2 Bell states are shared among A & B in the following way:
First Bell state $|...
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0answers
42 views
Determining the quantum secret
I earlier posted I question Representing a Bell measurement on non adjacent qubits for which I got an excellent answer. Now I want to build upon that and do further analysis which is where I am stuck. ...
1
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1answer
66 views
Representing a Bell measurement on non adjacent qubits
I have a state
$${|\psi\rangle} = s {\Bigl(|1\rangle_1|1\rangle_2-|0\rangle_1|0\rangle_2\Bigr)}\otimes{\Bigl(|0\rangle_3|1\rangle_4-|1\rangle_3|0\rangle_4\Bigr)}\otimes{\Bigl(|0\rangle_5|1\rangle_6-|1\...
2
votes
1answer
73 views
If Alice and Bob share a Bell state, can Alice send her individual qubit to a third party?
Suppose Alice wants to send Bob information. Each of them has been sent each of the qubits of the Bell state in advance. Suppose Alice has the first qubit and Bob has the second.
$|\Phi^+\rangle = \...
2
votes
2answers
54 views
Projecting $\lvert ++ \rangle$ on Bell Basis
I understand that, projecting $\lvert 00\rangle$ on the Bell states would produce $\lvert\Phi^+\rangle$. Because,
$$
CNOT(H\lvert0\rangle \otimes \lvert0\rangle) = \frac{1}{\sqrt{2}}(\lvert00\rangle +...
