What do we mean by exciting a superconducting circuit--which represent a qubit, how they are get excited inside? how the two states of the qubit are represented in this circuit?
Asked
Viewed
27 times
2
$\begingroup$
$\endgroup$
-
1$\begingroup$ I think this question is very broad, a superconducting qubit behaves like an quantum anharmonic oscillator, you can find a lot of the theory for example here $\endgroup$ – user2723984 Aug 7 at 8:46
-
1$\begingroup$ For a simple type of SC qubit (Cooper Pair Box), the device consists of a superconducting island connected to the mainland by a Josephson junction. Then the states $|0\rangle$ and $|1\rangle$ directly map to "cooper pair not on island" and "cooper pair on island" respectively $\endgroup$ – forky40 Aug 8 at 18:38
