As discussed in this question, the expected security of 1024-bit RSA is 80-bits:
NIST SP 800-57 §5.6.1 p.62–64 specifies a correspondence between RSA modulus size $n$ and expected security strength $s$ in bits:
Strength RSA modulus size 80 1024 112 2048 128 3072 192 7680 256 15360
According to Wikipedia, we now have a 20-qubit quantum computer:
IBM Q System One is a 20-qubit computer.
Question: If we tried to use a 20-qubit computer, e.g. IBM Q System One, to calculate the $\sim {2}^{80}$ keys in the 1024-bit RSA keyspace, how long would it take?