4
$\begingroup$

Say I have an algorithm over N qubits and I want to find the expectation value of an operator $O$ composed of a sum of mterms, each of which is the tensor product of some number of single-qubit Pauli operators:

$$ O = \sum_{i=1}^m \alpha_i \prod_{j=1}^N \sigma_{\beta(i,j)}^{(j)} $$

where $\beta(i,j) \in \{{0,1,2,3}\}$ determines the identity of the j-th Pauli operator in the i-th product in the sum ($\sigma_0 \equiv I$, $\sigma_1 \equiv X$, ...) and $\sigma^{(j)}$ denotes a Pauli operator acting on the j-th qubit. The goal is to determine the following:

  1. What is the minimum number of circuit experiments needed to completely evaluate $\langle O \rangle$ (a "circuit experiment" means as many measurements as I want for a given configuration of measurement bases over all N qubits)
  2. How do I find the elements of the maximally reduced set of measurement bases that accomplish (1).

Example a: $$ O = Z_1 + Z_2 + Z_3 + Z_1 Z_2 $$

  1. The minimum number of experiments is 1.

  2. The maximally reduced set of measurement operators is $\{Z_1 Z_2 Z_3\}$, which corresponds to measuring all three qubits in the Z-basis. From outcomes of these measurement bases, I can separately compute $\langle Z_1 \rangle $, $\langle Z_2 \rangle $, $\langle Z_3 \rangle $, and $\langle Z_1 Z_2 \rangle $ and then add the results to find $\langle O \rangle$. In general, I'm allowed to combine terms that have identical Pauli products on their overlapping subspace.

Example b: $$ O = X_1 Y_2 + Y_1 X_2 + X_1 X_2 + Y_1 Y_2 $$

  1. The minimum number of experiments is 4.
  2. The maximally reduced set is $\{ X_1 Y_2 , Y_1 X_2 , X_1 X_2 , Y_1 Y_2\}$. Even though in the course of measuring $\langle X_1 Y_2 \rangle$ and $\langle Y_1 X_2\rangle$ I measured both qubits in both bases, I cannot reuse the results from those measurements to determine $\langle X_1 X_2 \rangle$ because I lose any information about classical correlations in the outcomes of $X_1$ and $X_2$ (i.e. entanglement) if I try to combine their outcomes taken in two separate experiments.

So, given an arbitrary $O$ how do I find the minimum number of experiments and the corresponding maximally reduced set of measurements

$\endgroup$
  • $\begingroup$ I am confused with $O$, if it's an operator its expectation value depends upon the state/density matrix. $\endgroup$ – Hemant May 31 '19 at 3:15
  • $\begingroup$ without restrictions on the possible type of circuit, I would argue that the answer is always one. If I understand what you are saying, you can always use a circuit that "spreads" the correlation over a big number of modes, and then a single measurement configuration is enough to fully characterise the output states. See e.g. references in arxiv.org/abs/1806.02436 $\endgroup$ – glS Jun 3 '19 at 14:16
  • $\begingroup$ @glS I'm skeptical about "spreading" the information around in this context (no-cloning theorem) but haven't read the full paper, but either way the goal here is to avoid ancillas and just prepare another copy of $|\psi\rangle$ if necessary. $\endgroup$ – forky40 Jun 5 '19 at 0:24
  • $\begingroup$ Although if its easy to demonstrate that the answer is "1" for example b I would be interested in seeing that method $\endgroup$ – forky40 Jun 5 '19 at 0:25
  • 1
    $\begingroup$ Again it seems my lazy notation is to blame. For the state you gave, If I perform an experiment where I measure both qubits and record the outcome bitstring, with enough statistics I would compile a histogram that looks like {"00": $|a|^2$, "01" $|b|^2$, ...}. This histogram contains all of the information needed to compute <Z1Z2>, <Z1>, <Z2>. The number of histograms I need to do this (and their measureemnt bases) is what I meant by the "maximally reduced set of measurement bases". $\endgroup$ – forky40 Jun 6 '19 at 15:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.