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I want to implement a controlled operation that involves the following: we have the following qubits: $|x_0\rangle,|x_1\rangle,|0\rangle,|1\rangle,|z_0\rangle,|z_1\rangle$. I want to add the first four qubits as $|x_0x_1\rangle$ and $|01\rangle$ where each $x_i\in\{0,1\}$ conditioned on the $|z_1\rangle$ being $0$. If the control is $1$ then do not perform the adder mod operation. So the circuit for this that I constructed is given in the figure:

Controlled ADD MOD 4

Is this circuit correct?

Edit: Just to elaborate what this circuit does. It takes $3$ non-negative integer inputs $x=|x_0x_1\rangle$, $1=|01\rangle$, $z=|z_0z_1\rangle$ and adds the first two integers that are stored in the register $|x_0x_1\rangle$ and $|10\rangle$. The third integer $|z\rangle$ gives a remainder of $2$ when divided by $4$, but this can be thought of as the least significant bit being equal to $0$. Is the problem statement and circuit construction matching?

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  • $\begingroup$ What does $z_0$ do? $\endgroup$ – Mark S May 16 at 19:08
  • $\begingroup$ $z_0$ is not required for this computation but it will he used for further operation. at this moment it does not play a part $\endgroup$ – Upstart May 16 at 19:11
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The second from the top wire should probably be marked $|x_1 \rangle$ instead of $|x_0 \rangle$ (right now you have two $|x_0 \rangle$s). Other than that, the circuit looks correct for the described task.

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  • $\begingroup$ yes that is $|x_1\rangle$ $\endgroup$ – Upstart May 16 at 20:08

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