I am trying to figure out how to use the functions "_make_pred_succ_maps". Here is a description of the function from Github:

def _make_pred_succ_maps(self, n):
    """Return predecessor and successor dictionaries.
        n (int): reference to self.multi_graph node id
        tuple(dict): tuple(predecessor_map, successor_map)
            These map from wire (Register, int) to predecessor (successor)
            nodes of n.

Nevertheless, I do not understand how to interpret outputs like the following:

>>> circuit_name._make_pred_succ_maps(1)
({}, {(QuantumRegister(3, 'a'), 0): 10})

>>> circuit_name._make_pred_succ_maps(2)
({(QuantumRegister(3, 'a'), 0): 41}, {})

What do the individual numbers mean?

  • 1
    $\begingroup$ I'm not familar with this function, but QuantumRegister(3, 'a') describes a register of three qubits, with the register assigned the name 'a'. $\endgroup$ – James Wootton Mar 8 at 15:20
  • $\begingroup$ @JamesWootton Thank you for this info. Do you know what the other numbers mean? $\endgroup$ – Samuel Bosch Mar 9 at 16:06

(QuantumRegister(3, 'a'), 0) means the 0th qubit in a QuantumRegister called 'a' of size 3.

The other numbers (10 and 41) are node ids for the predecessors and successors of the node.

So what ({(QuantumRegister(3, 'a'), 0): 41}, {}) is saying is there is an edge from node 41 along wire (QuantumRegister(3, 'a'), 0) that ends at node 2 (the node you provided) and that this node has no successors as the second dict is empty.

It is also worth noting this is a private function and so should not really be used in this way.


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