3
$\begingroup$

This is really a question out of curiosity. I am aware that geometric algebra and geometric calculus provide simplifications in many aspects of physics. I'm wondering if this framework's usefulness extends to the realm of quantum computing.

$\endgroup$
1

1 Answer 1

2
$\begingroup$

The algebra generated over $\mathbb{C}$ by $\sigma_{x,y,z}$ gives $\text{Cliff}(\mathbb{R}^{3,0})$. But this doesn't really use more of the general features of Clifford algebra for general $\mathbb{R}^{p,q}$. You can phrase it in terms of Clifford algebra if you want, but not necessary for small examples.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.