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I'm going through this paper Step-by-Step HHL Algorithm Walkthrough, and wondering how to calculate an unnormalized solution $|x \rangle$ after measuring its b-register and ancilla qubit.

In equation (66), the state after applying IQPE is written as :

$| \psi_9 \rangle = \frac{2}{3} \sqrt{\frac{8}{5}} \left( - \frac{1}{\frac{2}{3} \sqrt{2} } | u_0 \rangle + \frac{1}{\frac{4}{3} \sqrt{2} } | u_1 \rangle \right) | 00 \rangle | 1 \rangle $

As the probability of measuring $ | 0 \rangle_b | 1 \rangle_a$ and $ | 1 \rangle_b | 1 \rangle_a$ are $0.063$ and $0.564$ in FIGURE 4, is the solution $| x \rangle$ calculated as follows?

$| x \rangle = \frac{1}{\frac{2}{3} \sqrt{\frac{8}{5}}} \left( \sqrt{0.063}\|0 \rangle + \sqrt{0.564}\|1\rangle \right) $

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