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The following code is a simple repetition code (for two qubits and one ancilla) for detecting Z errors:

eps = 0.1

circuit = stim.Circuit()
circuit.append("RX", [0,1,2])

circuit.append("DEPOLARIZE2", [0,2], eps)
circuit.append("CNOT", [2,0])
circuit.append("CNOT", [2,1])

circuit.append("MRX", [2])
circuit.append("DETECTOR", [stim.target_rec(-1)])


circuit.append("CNOT", [2,0])
circuit.append("CNOT", [2,1])

circuit.append("MRX", [2])
circuit.append("DETECTOR", [stim.target_rec(-2),stim.target_rec(-1)])

enter image description here

Errors on detections are different from the ones I expect to get from a transferring depolarzing2 to z2_error model [e---->(12/15 * e)]. In other words, I would expect to get error 4*e/15 for each detection D0, D1, and {D0D1}. I am wondering what I am missing.

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  • $\begingroup$ Does this answer your question? quantumcomputing.stackexchange.com/questions/38535/… $\endgroup$
    – Craig Gidney
    Commented Jun 12 at 22:28
  • $\begingroup$ Yes, that is exactly what I was asking for. I now understand general prospects, but in that example (when removing X error, only having depolarizing ones) I expect D0 D1 to be the same as depolarizing channel is symmetric. but you put different errors for them: error(0.08) D0 error(0.16) D1. So now I am confused about that. $\endgroup$
    – reza
    Commented Jun 13 at 16:01
  • $\begingroup$ probably just a typo $\endgroup$
    – Craig Gidney
    Commented Jun 13 at 16:58
  • $\begingroup$ Ah, ok. Thanks again for the clarification. $\endgroup$
    – reza
    Commented Jun 13 at 21:33

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