Does anyone know how to work with SwitchCaseOp? I want to use it as a tool to execute conditioned circuits. I have read the documentation, however, I can not figure out how to use it and run it on a simulator. It will be a great asset if you can help me on the matter.

  • $\begingroup$ Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. $\endgroup$
    – Community Bot
    Oct 14, 2023 at 17:49

1 Answer 1


The example in https://qiskit.org/documentation/apidoc/qasm3.html explains how switch works:

from qiskit.circuit import QuantumCircuit, ClassicalRegister, QuantumRegister
qreg = QuantumRegister(3)
creg = ClassicalRegister(3)
qc = QuantumCircuit(qreg, creg)
qc.h([0, 1, 2])
qc.measure([0, 1, 2], [0, 1, 2])

with qc.switch(creg) as case:
    with case(0):
    with case(1, 2):
    with case(case.DEFAULT):
        qc.cx(0, 1)

qc.measure([0, 1, 2], [0, 1, 2])

However, it also has a note that says that its support is experimental as it depends on https://github.com/openqasm/openqasm/pull/463 . So simulators do not support it yet.

For this reason, the OpenQASM3 dumper needs the SWITCH_CASE_V1 experimental flag:

from qiskit import qasm3
qasm_string = qasm3.dumps(qc, experimental=qasm3.ExperimentalFeatures.SWITCH_CASE_V1)
...     # some of the output removed
c4[0] = measure q4[0];
c4[1] = measure q4[1];
c4[2] = measure q4[2];
switch_dummy = c4;
switch (switch_dummy) {
  case 0: {
    x q4[0];
  case 1:
  case 2: {
    z q4[1];
  default: {
    cx q4[0], q4[1];

A short explanation:

  1. switch_dummy = c4; switch (switch_dummy): The switch condition is over the full classical register
  2. case 0: {: If the integer representation of creg is 0.
  3. case 1: and case 2:: If creg is a 1 or a 2 (consider creg is a 3 bit-long signed integer).
  4. default: This branch is for any other case.
  • $\begingroup$ Thank you so much for your attention to my question. It means the world to me. Just I do not know how the condition works here. For example with qc.if_test(), we can have a condition on the outcome of our measurement saved in a classical register. Then whether being 0 or 1, we apply arbitrary gates on the circuit. But here, how does the condition work? $\endgroup$ Oct 15, 2023 at 20:40
  • $\begingroup$ I added extra information using OpenQASM3 as a middle language. $\endgroup$
    – luciano
    Oct 16, 2023 at 6:40
  • $\begingroup$ Wow, that was a really great explanation. Thank you so much! $\endgroup$ Oct 17, 2023 at 16:02

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