0
$\begingroup$

$\newcommand\bra[1]{\left\langle#1\right|}\newcommand\ket[1]{\left|#1\right\rangle} $ I am having a little bit of difficulty with part (4) of Exercises 2.72 from Nielsen and Chuang's "Quantum Computation and Quantum Information".

It asks us to show that "for pure states the description of the Bloch vector we have given ($\rho=\frac{I + r.\sigma}{2}$ ) coincides with that in section 1.2 (($\ket{\psi} = \cos(\frac{\theta}{2})\ket{0} + e^{i \phi} \sin(\frac{\theta}{2}) \ket{1}$, for $\ket{\psi}$ is on the surface of the Bloch sphere))

I have found that $\rho = \cos^{2}(\frac{\theta}{2}) \ket{0} \bra{0} + \frac{e^{-i \phi}\sin(\theta)}{2}\ket{0}\bra{1} + \frac{ e^{i \phi} \sin{\theta} }{2} \ket{1} \bra{0} + \sin^{2}(\frac{\theta}{2}) \ket{1} \bra{1}$

This is where I am stuck. A couple of the solutions online have said that

$\rho = \frac{I + r. \sigma}{2}$ can be expressed (in the computational basis) as: $$ \rho = \frac{1 + r_{z}}{2} \ket{0} \bra{0} + \frac{r_{x} - i r_{y}}{2} \ket{0} \bra{1} + \frac{r_{x} + i r_{y}}{2} \ket{1} \bra{0} + \frac{1 - r_{z}}{2} \ket{1} \bra{1}$$ I really don't understand how we get the above representation?

(Note that here $r$ is a three dimensional vector whose norm is less than or equal to $1$)

$\endgroup$
7
  • 1
    $\begingroup$ so are you trying to find the vector $\vec{r}$? $\endgroup$
    – BeauGeste
    Jul 19, 2023 at 13:56
  • $\begingroup$ I think I found that the vector r is $<2a_{2}, 2a_{3}, 2a_{4}>$, where $a_{2}, a_{3}, a_{4}$ are the coeffiecients of the $X, Y, Z$ respectively for an arbitrary density matrix $$\rho = a_{1}I + a_{2}X + a_{3}Y + a_{4}Z$$ $\endgroup$
    – am567
    Jul 19, 2023 at 16:05
  • $\begingroup$ $\newcommand\bra[1]{\left\langle#1\right|}\newcommand\ket[1]{\left|#1\right\rangle} $The part I am confused on is where did the coefficients of $$\ket{0}\bra{0}, \ket{0}\bra{1}, \ket{1}\bra{0}, \ket{1}\bra{1}$$ come from? $\endgroup$
    – am567
    Jul 19, 2023 at 16:06
  • $\begingroup$ have you tried writing that $\rho$ in terms of the Pauli matrices? $\endgroup$
    – BeauGeste
    Jul 20, 2023 at 2:22
  • 1
    $\begingroup$ related: quantumcomputing.stackexchange.com/a/4121/55 and quantumcomputing.stackexchange.com/q/5574/55 $\endgroup$
    – glS
    Aug 16, 2023 at 22:13

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.