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Trying to implement Grover under Qiskit I found an example with good_state = ['110','101'] For a given $n$ it possible to define good_state as "any string of $n$ bits whose last bit is 1"? And if so, how?

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Yes, there's two options:

  1. Define the good state as "1" and use only the last bit as objective qubit:
from qiskit.algorithms import EstimationProblem

stateprep = # your state preparation, or "A" operator
n = # index of your target qubit
problem = EstimationProblem(stateprep, objective_qubits=[n])  
# the good state default is 1, so you don't need to specify it, but if you want to:
# problem = EstimationProblem(stateprep, objective_qubits=[n], is_good_state="1") 
  1. Define the is_good_state via a function
from qiskit.algorithms import EstimationProblem

stateprep = # your state preparation, or "A" operator
n = # index of your target qubit

def is_good_state(bitstring):
    return bitstring[n] == "1"  # note: maybe the bitstring needs to be reverted

problem = EstimationProblem(stateprep, objective_qubits=list(range(n)), is_good_state=is_good_state) 

I would strongly suggest option 1, that'll generate the more efficient circuits.

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  • $\begingroup$ Thank you very much for your prompt and very helpful response! $\endgroup$ May 23 at 15:34

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