In Qiskit, I am looking for a convenient way to "strip-off" a QuantumCircuit object from its multiple QuantumRegister and ClassicalRegister objects, such that in the final QuantumCircuit object there will be only 1 QuantumRegister and 1 ClassicalRegister, without any loss of the circuit's qubits, bits or content.

I haven't found any built-in option in Qiskit for this feature so far. However, when I look at a job page in IBM Quantum website I see a QASM code of the job's circuit exactly as I am looking for (with 1 qreg and 1 creg). So I infer there is a convenient way to implement this.


1 Answer 1


The easiest way from the top of my head is to simply compose your multiregistered circuit to a flat one:

Say you have this circuit:

from qiskit import QuantumCircuit, QuantumRegister, ClassicalRegister

qreg1 = QuantumRegister(1, 'qreg1')
qreg2 = QuantumRegister(1, 'qreg2')
creg1 = ClassicalRegister(1, 'creg1')
creg2 = ClassicalRegister(1, 'creg2')
circuit = QuantumCircuit(qreg1, qreg2, creg1, creg2)
circuit.cx(qreg1, qreg2)
circuit.measure(qreg1, creg1)
circuit.measure(qreg2, creg2)
         ┌───┐     ┌─┐   
  qreg1: ┤ H ├──■──┤M├───
  qreg2: ─────┤ X ├─╫─┤M├
              └───┘ ║ └╥┘
creg1: 1/═══════════╩══╬═
                    0  ║ 
creg2: 1/══════════════╩═

You can compose it to a flat one like this, resulting in a circuit like the one you are searching for:

flat_circuit = QuantumCircuit(circuit.num_qubits, circuit.num_clbits)
flat_circuit.compose(circuit, inplace=True)
     ┌───┐     ┌─┐   
q_0: ┤ H ├──■──┤M├───
q_1: ─────┤ X ├─╫─┤M├
          └───┘ ║ └╥┘
c: 2/═══════════╩══╩═
                0  1 
  • $\begingroup$ Works perfectly, thanks. However I wonder if this method can be computationally costly when dealing with large circuits. $\endgroup$
    – Ohad
    Mar 6, 2023 at 5:55
  • $\begingroup$ the code in QuantumCircuit.compose iterates on other.data and copy it. So yes. It is not O(1). $\endgroup$
    – luciano
    Apr 12, 2023 at 9:40

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