2
$\begingroup$

How to determine an unknown quantum gate if we know all other gates in the circuit and the inputs and outputs?

Instead of doing this on pen and paper, how to solve the above question using qiskit. Is there any way that qiskit can do all the calculations and display the matrix of unknown gate and if feasible, can also give the name of the gate?

$\endgroup$

1 Answer 1

2
$\begingroup$

Yes, you can. You should define the quantum gate in a parametric way, set random parameters, execute the circuit and compare the output state with the desired one (using fidelity, for example), then repeat with updated parameters until convergence to the correct output state (fidelity = 1). Here the problem is: how to update the parameters in order to converge to the correct output state as soon as possible (i.e., with few iterations).

Here is some code to start with:

# This code works with qiskit 0.41

from qiskit import QuantumCircuit, transpile, execute, BasicAer
from qiskit.extensions import UnitaryGate
from qiskit.quantum_info import state_fidelity, Statevector
import numpy as np

# matrix of the gate
matrix = np.array([[1, 0, 0, 0],
                   [0, 0, 1, 0],
                   [0, 1, 0, 0],
                   [0, 0, 0, 1]], dtype=complex)
gate = UnitaryGate(matrix)

qc = QuantumCircuit(4)

qc.append(gate, [1, 2])

qc = transpile(qc, optimization_level=3, basis_gates=['u3','cx'])

qc.draw(output='mpl',filename='./circuit.pdf')

backend_sim = BasicAer.get_backend('statevector_simulator')

result = execute(qc, backend_sim).result()
out_state = result.get_statevector(qc)
#print(out_state)

ref_state = Statevector([1.-5.30216531e-16j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j, 0.+0.00000000e+00j])

F = state_fidelity(out_state,ref_state)
print(F)

In this example, the reference state is exactly the state computed by the circuit. If you modify the matrix, you will see a different value of fidelity F.

To proceed, you need to define the matrix in a parametric way, define a clever way to update the parameters, and put your code in a loop.

$\endgroup$
2
  • $\begingroup$ I am new to qiskit and don't know much. Could you refer to some notebooks where this is implemented? $\endgroup$
    – wizzywizzy
    Feb 5 at 13:49
  • $\begingroup$ There is no tutorial, but I added a piece of code that should be useful to start. $\endgroup$ Feb 5 at 15:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.