I am interested in the relation of the eigenvalues of two Hermitian operators $A$ and $B$ that are related via $$A = \sum_j c_j U_j B U^\dagger_j.$$
Is there anything useful I can say about the spectrum? It looks suspiciously similar to the case of a regular unitary transformation, i.e. where the eigenvalues are preserved. I wonder if something similar can be said here. I don't necessarily need to know the full spectrum, already just knowing that the spectrum is the same but stretched would be helpful.
I was trying the following: I can write $B = \sum_n \lambda_n |n \times n|$ where $\{\lambda_n\}$ is the spectrum of $B$. Plugging that into the definition above yields $$A = \sum_n \lambda_n \sum_j c_j U_j |n \times n| U^\dagger_j =: \sum_n \lambda_n \sum_j c_j |\tilde{n}_j \times \tilde{n}_j|$$ where $\tilde{n}_j = U_j |n\rangle$.
It almost looks like there should be a way to relate to the spectrum of $A$, but here I am stuck. Any ideas how to proceed?
Some specifications that may help reducing the complexity: The $U_j$ have the form $U_j = \exp(-i \phi_j \sum_\ell P_\ell)$ where $P_\ell$ are (non-commuting) Pauli-words and $B$ is one of those Pauli words. So to specify the original relation: $$ A = \sum_j c_j e^{i \phi_j \sum_\ell P_\ell} P_k e^{-i \phi_j \sum_\ell P_\ell} $$ Pauli word here means that it is a tensor product of Pauli-operators, e.g. $P_0 = X_1 \otimes Y_2$. The case that all $c_j\equiv 1$ may also be interesting.