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Is it possible to write a code to separate $\left|01\right> $ as $\left|0\right> ,\left|1\right> $ or are there any circuits i can use to get output like that?

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    $\begingroup$ $\left|01\right> $ is a register of 2 qubits. There is no circuit to separate them. You have to redefine your registers. One register for $\left|0\right>$ and another for $\left|1\right> $ . $\endgroup$ Jun 6 at 19:48
  • $\begingroup$ How can I assign a register to two qubits? $\endgroup$
    – User1086
    Jun 6 at 20:24
  • $\begingroup$ qiskit.QuantumCircuit(2) defines a register of 2 qubits. $\endgroup$ Jun 6 at 22:53
  • $\begingroup$ you can use qiskit.visualization.plot_bloch_multivector to visualize it $\endgroup$
    – poig
    Jun 10 at 16:24

2 Answers 2

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Maybe it should be useful tu use qutip to better understand what you desire (if you are familiar with python) by visualizing exactly the 2 qubits and its state vectors (which I believe is what you seek to visualize).

I recently made a post on my personal blog that can help with that start; if you are interested, you can check it here for more details

Hope it is useful somehow!

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I found a similar answer, might be something you are looking for
https://quantumcomputing.stackexchange.com/a/15514/20884

counts = job.result().get_counts(qc)
# New dictionary to store out results in.
new_counts = {'0': 0,
              '1': 0}

# The qubit we want the probability for
show_qubit = 1

for count in counts:
    count_idx = (len(count) - 1) - show_qubit
    new_counts[count[count_idx]] = new_counts[count[count_idx]] + counts[count]

print(new_counts)
plot_histogram(new_counts)
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  • $\begingroup$ Now if I want to split that into two qubits how can I assign I measure that quantum register and have state ex:$\left|01\right> $ as $\left|0\right> ,\left|1\right> $ $\endgroup$
    – User1086
    Jun 7 at 3:24
  • $\begingroup$ @User1086 may be you are talking about statevector. $\endgroup$
    – poig
    Jun 7 at 4:11

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