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Is there any function I can call to visualize a stim circuit?

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2 Answers 2

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Since v1.10, you can use stim.Circuit.diagram to visualize the circuit.

import stim

circuit = stim.Circuit("""
    QUBIT_COORDS(0, 0) 0
    QUBIT_COORDS(0, 1) 1
    QUBIT_COORDS(1, 0) 2
    QUBIT_COORDS(1, 1) 3
    R 0 1 2 3
    H 0 2
    CNOT 0 1
    CNOT 2 3
    M 0 1 2 3
""")

print(circuit.diagram())
q0: -QUBIT_COORDS(0,0)-R-H-@-M:rec[0]-
                           |
q1: -QUBIT_COORDS(0,1)-R---X-M:rec[1]-

q2: -QUBIT_COORDS(1,0)-R-H-@-M:rec[2]-
                           |
q3: -QUBIT_COORDS(1,1)-R---X-M:rec[3]-

You can also get an SVG image of the timeline:

circuit.to_diagram(type="timeline-svg")

In Jupyter notebooks this SVG will display inline. Otherwise you have to print it to a .svg file then open it.

enter image description here

or a 3d model, optionally embedded into a viewer that can be opened in a web browser:

# for this one you really want to have specified qubit coords
circuit.to_diagram(type="timeline-3d-html")

enter image description here

In Jupyter notebooks this viewer will display inline in the cell output. Otherwise you have to print it to a .html file then open it.

The diagram types that are currently available are:

    timeline-text
    timeline-svg
    timeline-3d
    timeline-3d-html
    match-graph-svg
    match-graph-3d
    match-graph-3d-html
    detector-slice-text
    detector-slice-svg

You can also use the stimcirq package to convert into a cirq circuit and get diagrams that way (e.g. with the cirq_web package).

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  • $\begingroup$ I notice when I have detectors in a stim circuit, the 3d visualization of cirq_web can not work properly. Is that true I must delete all the detectors for visualization with cirq_web? $\endgroup$
    – Inm
    Apr 1, 2022 at 6:33
  • $\begingroup$ @Inm That sounds like a bug in cirq_web to me; it should be ignoring operations with no targets. But yes, filtering out the bad instructions would avoid the problem. $\endgroup$ Apr 1, 2022 at 8:21
  • $\begingroup$ @Inm I reported the bug: github.com/quantumlib/Cirq/issues/5172 $\endgroup$ Apr 1, 2022 at 8:28
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You can use stimcirq to convert your Stim circuit into a Cirq circuit then visualize it:

import stim
import stimcirq

cirq_circuit = stimcirq.stim_circuit_to_cirq_circuit(stim_circuit)
print(cirq_circuit)
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