I am having trouble understanding what IBM's histogram is doing.
I have independently verified, in agreement with the statevector given from IBM, that after all these steps the statevector should be in the state:
$$ |\psi\rangle = \left(\frac{1}{\sqrt{6}}\> \frac{1}{\sqrt{6}}\>\frac{1}{\sqrt{6}}\>0\>\frac{1}{\sqrt{6}}\>\frac{1}{\sqrt{6}}\>\frac{1}{\sqrt{6}}\> 0 \> \ldots 0\right)^T $$
Where the dots stand in for 23 more 0's. When simulating measurement, I acquire the following Histogram:
Which matches up exactly with the absolute value of the squares amplitudes, which is what I believe the histogram should generate, especially after this answer confirmed as much.
However IBM does not generate this histogram, it generates the following histogram:
which is exactly the histogram I generate independently when I ignore the resets.
Does IBM have an error when dealing with Resets, or am I misunderstanding something?