I have written the following program in jupyter:

from qiskit import *
from qiskit import plot_histogram, matplotlib

circuit = QuantumCircuit(16,16) #Making a circuit with 16 qubits
qr = QuantumRegister(16)
cr = ClassicalRegister(16)
for i in range(16):

simulator = Aer.get_backend('qasm_simulator')
result = execute(circuit, backend = simulator, shots = 200).result()
counts = result.get_counts()

and the output is of the form :

{'0111001100011110': 1, '0101000101101001': 1, '1100010111000100': 1, 
'0111111110101110': 1,..., '0110110010010110': 1}

Is there any way that what I get as an output is the measurement only (e.g. '0111001100011110') without getting the times the measurement has appeared (: 1)?

  • $\begingroup$ A bit of a side note: circuit.h(qr); circuit.measure(qr, cr) is equivalent to that for-loop. $\endgroup$
    – luciano
    Aug 26, 2021 at 13:51

1 Answer 1


You can take only the keys of the returned dictionary:

measurements = set(counts.keys())

If you want only one random key, you can just take the first one in the set:

random_key = next(iter(a))

or store all the keys in a list and take a random one from here:

from random import randint
measurements_list = list(measurements)
random_key = measurement_list[randint(0, len(measurement_list)-1)]
  • $\begingroup$ Thank you. That is exactly what I needed! $\endgroup$
    – Assassinos
    Aug 26, 2021 at 9:23

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