# Why is H gate called a ‘square-root of NOT’ gate?

In Nielsen and Chuang, there's the following paragraph: I understand that \begin{align*} \sqrt{NOT} = \frac{1}{2}\left( {\begin{array}{*{20}{c}} \sqrt 2 e^{i\pi / 4}&\sqrt 2 e^{-i\pi / 4}\\ \sqrt 2 e^{-i\pi / 4}&\sqrt 2 e^{i\pi / 4} \end{array}} \right) \\ \end{align*}

But, I'm still confused how the H gate is related to the ‘square-root of NOT’ gate.

• It is already explained in the paragraph you copied to your question. Hadamard is "like" square root in sense that turns a qubit to half-way between states $|0\rangle$ and $|1\rangle$. There is also stated that $H^2$ is not $X$. Hence there is no relation to square root of $X$. Aug 3, 2021 at 9:45

I don't think the Hadamard gate is ever actually called "square root of NOT". I'd guess the emphasis in this sentence is on the word "like", in that it possesses the same property of converting the basis states into states halfway between the basis states, though the Hadamard gate does it without adding complex phases, and the $$\sqrt{NOT}$$ throws in complex numbers.