I've the following circuit which gives an output of
1 with a phase angle of
3π/4. When we measure the circuit all we get is the state
1 (On actual QC, it's 90% of the time
1). Is the information about the phase angle lost by measuring the state? Could the phase angle also be part of the output?
OPENQASM 2.0; include "qelib1.inc"; qreg q; creg c; u(pi/2,pi/2,0) q; h q; u(pi/2,pi/2,pi/2) q; measure q -> c;