Among some documents I found to make a MPS state on quantum circuit, I can make it with stepped arrangement of unitary operators.


And also Honeywell or IBM machine support Mid-circuit measurement and qubit reuse, which we can fold this quantum circuit like,

|0>--U--M |0>--U--M
     |         |

How can I think about bond dimension on this quantum circuit? Do I have to use multiple qubits to make larger number of bond dimension on MPS state?

  • $\begingroup$ Can you explain what U and what M is? Are the two U's connected by a vertical line one big unitary? And what's the point of the folding picture with regard to your question? $\endgroup$ Commented Mar 12, 2021 at 21:59
  • $\begingroup$ yes thank you. M is measurement and U is a large unitary with one qubit arbitrary rotation and two qubits arbitrary rotations. $\endgroup$
    – gojo
    Commented Mar 14, 2021 at 2:24


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