# How is it possible for Quantum computers to handle encryption if their states are unstable?

I've been doing research on quantum computers and encryption. How is it possible for quantum computers to solve complex encryption algorithms while their qubit states are not even predictable? How is it even possible for them to implement vectoring? Quantum registers do not sound like they are even stable enough to perform any kind of predictable math alone. How are errors in state detected and/or discarded?

• In essence, qubits (your so-called "quantum registers") have radically different properties than bits (which holds the discrete set of values 0 and 1) enabling them to be used to construct otherworldly mathematical objects that works fundamentally different from your so-called "predictable math", which are effecient at solving certain class of problems that may be difficult for bit-based computers to solve. Feb 10 at 6:04
• I was under the impression that qubits were translated into a separate stateful registry after their state was mathematically predicted. Feb 10 at 15:49

Statea of quantum computer are not unstable or unpredictable. For now, put aside a noise and assume ideal quantum computer. Any state can be desribed by a vector in space $$C^{2^n}$$, where $$n$$ is number of qubits. Any operation (with exception to reset and measurement) is a unitrary matrix from space $$C^{2^n,2^n}$$. So far everything is perfectly predictable. Of course, when you measure a state, you get a random results but this is determined by the vector describing the state (or in other words by probability distribution or wave function). This all mean that a quantum computer behaves in predictable way even though its nature is probabilistic.
Now on noise, yes it is true that the noise is unpredictable. However, to eliminate the noise is a matter of engineering and development. There is a so-called threshold theorem which states that with sufficiently large number of qubits you are able to reduce noise under certain level $$\epsilon.$$