1
$\begingroup$

I've been trying to find in textbooks a discussion on the action of arbitrary single qubit gates on a lexicographic state. That is, given an operator $G_{l}= 1\otimes 1...\otimes G \otimes ... \otimes 1$ which acts on the $l$-th qubit and a state

$|\psi\rangle = \sum \alpha_{J} |J\rangle$

where $ 0 \leq J < 2^N $, $N$ is the number of qubits, $J \in \mathbb{Z}$, $|J\rangle$ is standard product state representing $J$ in binary, and the sum runs through the range of J, what can be said about:

$G_{l} |\psi \rangle$

in terms of the single qubit operator $G$ and how do the original $\alpha_{J}$ map.

It shouldn't be too difficult to derive some formulas (there will likely be some transitions between $J$ and it's bit flipped int) but I figured since this seems like a basic thing it would have been discussed somewhere.

Edit: Using the notation of the answer below it's can be shown that if:

$G = g_{00} |0\rangle \langle 0| + g_{01} |0\rangle \langle 1| + g_{10} |1\rangle \langle 0| + g_{11} |1\rangle \langle 1|$

then the coefficent mappings are:

$\alpha'_{J} = \alpha_J g_{00} + \alpha_{f_l(J)} g_{01} $ if $J_{l} = 0$

$\alpha'_{J} = \alpha_J g_{11} + \alpha_{f_l(J)} g_{10} $ if $J_{l} = 1$

where $f_l(J)$ flips the $l$-th bit of $J$.

$\endgroup$

1 Answer 1

1
$\begingroup$

That $G_{l}$ action is linear, so you can write $$ G_{l} |\psi \rangle = G_{l} \sum \alpha_{J} |J\rangle = \sum \alpha_{J} G_{l} |J\rangle. $$

To calculate $G_{l} |J\rangle$ you can use tensor mixed-product property:

$$ G_{l} |J\rangle = \big(1\otimes ...\otimes G \otimes ... \otimes 1\big) ~\cdot~ \big(|J_1\rangle \otimes ... \otimes |J_l\rangle \otimes ... \otimes |J_N\rangle\big) = $$ $$ = |J_1\rangle \otimes ... \otimes G|J_l\rangle \otimes ... \otimes |J_N\rangle, $$ here $J_i$ is the $i$-th bit of $J$.

You can simplify the total sum by grouping terms in two groups based on the value of $J_l$: $$ G_{l} |\psi \rangle = \sum_{J_l=0} \alpha_{J} |J_1... J_{l-1}\rangle \otimes G|0\rangle \otimes |J_{l+1} ...J_n\rangle + $$ $$ + \sum_{J_l=1} \alpha_{J} |J_1... J_{l-1}\rangle \otimes G|1\rangle \otimes |J_{l+1} ...J_n\rangle $$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.