I've been trying to find in textbooks a discussion on the action of arbitrary single qubit gates on a lexicographic state. That is, given an operator $G_{l}= 1\otimes 1...\otimes G \otimes ... \otimes 1$ which acts on the $l$-th qubit and a state
$|\psi\rangle = \sum \alpha_{J} |J\rangle$
where $ 0 \leq J < 2^N $, $N$ is the number of qubits, $J \in \mathbb{Z}$, $|J\rangle$ is standard product state representing $J$ in binary, and the sum runs through the range of J, what can be said about:
$G_{l} |\psi \rangle$
in terms of the single qubit operator $G$ and how do the original $\alpha_{J}$ map.
It shouldn't be too difficult to derive some formulas (there will likely be some transitions between $J$ and it's bit flipped int) but I figured since this seems like a basic thing it would have been discussed somewhere.
Edit: Using the notation of the answer below it's can be shown that if:
$G = g_{00} |0\rangle \langle 0| + g_{01} |0\rangle \langle 1| + g_{10} |1\rangle \langle 0| + g_{11} |1\rangle \langle 1|$
then the coefficent mappings are:
$\alpha'_{J} = \alpha_J g_{00} + \alpha_{f_l(J)} g_{01} $ if $J_{l} = 0$
$\alpha'_{J} = \alpha_J g_{11} + \alpha_{f_l(J)} g_{10} $ if $J_{l} = 1$
where $f_l(J)$ flips the $l$-th bit of $J$.